Interpreting Paternity Results

Before we begin a detailed explanation of how to interpret a DNA paternity report, it is important to define some terms we will use.

Definition of Terms

Paternity Index
This value equals the odds that the alleged father is the biological father rather than any other man selected at random from the population. The minimum PI issued by Orchid PRO-DNA in a court ready test is 1000.

Combined Paternity Index
Since the result at each Genetic System is an independent event, this value is the product of the Paternity Indices and indicates the possibility of the alleged father being the biological father relative to any other man selected at random from the population.

Probability of Paternity
This value is converted from the "Combined Paternity Index" into the percentage probability.

Prior Probability
The prior probability in a paternity test is 0.50 which is 50%. That means that, without testing any of the parties, there is a 50% chance that any untested man is the father and a 50% chance that he is not the father. The Probability of Paternity obtained as a result of an actual DNA test can be compared to this Prior Probability.

Interpretation of Results

The results of a routine paternity test will indicate a probability of paternity of either 0.00% or 99.9% or greater.

If the alleged father and child do not share any of the same DNA, then the alleged father is not the father of the child. This is called an "EXCLUSION" and the probability of paternity will be 0.00%.

If the child and alleged father share the same DNA, then this is considered a "NON EXCLUSION" (i.e. the alleged father cannot be excluded as the biological father) and a probability of paternity will be calculated. The minimum probability of paternity in a non-exclusion will be 99.9%.

A DNA paternity report can never provide a 100% probability of paternity because that would require comparing the DNA of the tested man to every other man on this earth, and that is not possible.

Please note that all DNA paternity reports issued by Orchid PRO-DNA assume that any alternative alleged fathers are unrelated to the tested man.

The two diagrams below provide examples of both a Non-Exclusion and an Exclusion.

EXAMPLE OF A NON-EXCLUSION RESULT

System Mother Child Alleged
Father
Paternity
Index
D3S1358 14 , 18 14, 15 15 , 16 4.03
vWA 14 , 17 14 , 17 14 , 17 2.72
FGA 18 , 24 18 , 22 22 , 24 2.81
D8S1179 13 13 , 14 11 , 14 1.49
D21S11 31.2 , 33.2 30 , 31.2 30 3.88
D18S51 14 14 14 , 17 2.94
D16S539 9 , 12 9 , 11 11 , 12 1.57
TH01 7 , 9.3 7 , 9.3 7 , 9.3 1.41
D2S1338 19 , 24 19 , 24 19 , 23 1.89
D19S433 13 , 14 14 , 17.2 13 , 17.2 39.00

 

  1. Identify the two alleles (numbers) for the child at each system. (e.g. the child has a 14, 15 at system D3S1358)
  2. Determine which of the child’s alleles come from the mother. (e.g. at system D3S1358, the mother (14,18) gives the child (14,15) a 14)
  3. Therefore the alleged father must provide the child with the other allele, a 15. (e.g. at system D3S1358, the alleged father (15,16) provides the child (14,15) with the 15)
  4. This matching between the child and alleged father at system D3S1358 is an example of a non-exclusion.
  5. Once the alleles are analyzed for all systems, population statistics are then calculated based upon the paternal alleles provided to the child. The result is a Paternity Index for each system.
  6. The final calculation involves the multiplication of each Paternity Index with the others to come up with a Combined Paternity Index value. For example, the Paternity Index of system D3S1358 is 4.03 and the Combined Paternity Index for the overall results is 85,426. This means that the odds of the tested man being the biological father is 85,426 times to 1.

 

EXAMPLE OF EXCLUSION RESULT

System Mother Child Alleged
Father
Paternity
Index
D3S1358 14 , 18 14,15 17,18 0.00
vWA 14 , 17 14 , 17 14 , 20 2.72
FGA 18 , 24 18 , 22 23,25 0.00
D8S1179 13 13 , 14 8 , 14 1.49
D21S11 31.2 , 33.2 30 , 31.2 30,35 3.88
D18S51 14 14 15,18 0.00
D16S539 9 , 12 9 , 11 11 , 15 1.57
TH01 7 , 9.3 7 , 9.3 6 , 9.3 1.41
D2S1338 19 , 24 19 , 24 19 , 20 1.89
D19S433 13 , 14 14 , 17.2 15,16 0.00

 

  1. Identify the two alleles (numbers) for the child. (e.g. the child has a 14, 15 at system D3S1358)
  2. Determine which of the child’s alleles come from the mother. (e.g. at system D3S1358, the mother (14,18) gives the child (14,15) a 14)
  3. Therefore the alleged father must provide the child with the other allele, a 15. However the tested alleged father is a 17,18 and could not have provided the child with a 15.
  4. This mis-match between the child and alleged father at system D3S1358 is an example of an exclusion and the paternity index becomes 0.00 for this system.
  5. If the child and alleged father do match, by chance, population statistics are used to derive a paternity index for that system.
  6. When the statistical calculations are applied to the all of the paternity index results in the above case, the Combined Paternity Index is 0.00 and therefore there is a 0% probability of paternity.

** A Combined Paternity of Index of 100 to 1 is required by Accreditation Standards to report an Inclusion.

** At least 2 Exclusion Systems must be found by Orchid's internal standards to report an Exclusion.

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